An engine pumps water continuously through a hose. Water leaves the hose with velocity $v$ and $m$ is mass…

An engine pumps water continuously through a hose. Water leaves the hose with velocity $v$ and $m$ is mass per unit length of the water jet. If this jet hits a surface and came to rest instantaneously, the force on the surface is
  1. $m v^3$
  2. $m v^2$
  3. $\frac{1}{2} m v^2$
  4. $\frac{1}{2} m v^3$

Solution

As power $\mathrm{P}=F . v .=\frac{F \ell}{t}$ $ $ \begin{aligned} & \text { or, } v\left(M \frac{v}{t}\right)=\frac{F . \ell}{t} \\ & \Rightarrow \quad M v^2=F \ell \ell \\ & \Rightarrow \quad F=\frac{M}{\ell} v^2=m v^2 \\ & {\left[\because \frac{M}{\ell}=m(\text { given })\right]} \end{aligned} $ $

Asked in: JEE Main 2012 (07 May Online)

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