An engine operates by taking n   moles of an ideal gas through the cycle A B C D A shown in figure. The…

 An engine operates by taking n moles of an ideal gas through the cycle ABCDA shown in figure. The thermal efficiency of the engine is:

(Take Cv=1.5R, whereR is gas constant)

  1. 0.24
  2. 0.15
  3. 0.32
  4. 0.08

Solution

Work done in cycle =area under closed curve

W=P0V0

Heat given =QAB+QBC

=nCV ΔTAB+nCp ΔTBC

=32nRTB-nRTA+52nRTC-nRTB

=322P0V0-P0V0+524P0V0-2P0V

=132 P0V0

Thermal efficiency, η=WQabsorbed=213=0.15

Asked in: JEE Main 2017 (08 Apr Online)

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