An engine is attached to a wagon through a shock absorber of length 1 . 5   m . The system with a total mass of 40 , 000   kg is moving with a speed of 72   km   h - 1 when the brakes are applied to bring it to rest. In the process of the system being brought to rest, the…

Question

An engine is attached to a wagon through a shock absorber of length 1 . 5 &#160; m . The system with a total mass of 40 , 000 &#160; kg is moving with a speed of 72 &#160; km &#160; h - 1 when the brakes are applied to bring it to rest. In the process of the system being brought to rest, the spring of the shock absorber gets compressed by 1 . 0 &#160; m . If 90 % of energy of the wagon is lost due to friction, the spring constant is _ _ _ _ _ _ _ _ _ &#215; 10 5 &#160; N &#160; m - 1 .

Aicharya · Accepted Answer

Work = &#916; K . E . W triction&#160; + W spring&#160; = 0 - 1 2 m v 2 - 90 100 1 2 m v 2 + W spring&#160; = - 1 2 m v 2 w spring&#160; = - 10 100 &#215; 1 2 m v 2 - 1 2 k x 2 = - 1 20 m v 2 &#8658; k = 40000 &#215; ( 20 ) 2 10 &#215; ( 1 ) 2 = 16 &#215; 10 5

An engine is attached to a wagon through a shock absorber of length 1 . 5   m . The system with a total…

Solution

An engine is attached to a wagon through a shock absorber of length 1 . 5 &#160; m . The system with a total…

Solution

An engine is attached to a wagon through a shock absorber of length 1 . 5 m . The system with a total…