An ellipse is drawn by taking a diameter of the circle $(x-1)^2+y^2=1$ as its semiminor axis and a diameter…

An ellipse is drawn by taking a diameter of the circle $(x-1)^2+y^2=1$ as its semiminor axis and a diameter of the circle $x^2+(y-2)^2=4$ as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is
  1. $4 x^2+y^2=4$
  2. $x^2+4 y^2=8$
  3. $4 x^2+y^2=8$
  4. $x^2+4 y^2=16$

Solution

Semi minor axis $b=2$ Semi major axis $a=4$ Equation of ellipse $=\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 \quad \Rightarrow \frac{x^2}{16}+\frac{y^2}{4}=1$ $\Rightarrow x^2+4 y^2=16$.

Asked in: JEE Main 2012 (Offline)

Practice more Conic Sections questions on Aicharya