An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68…

An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg . The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s . The frictional force opposing the motion is 6000 N . If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator g=10m/s2 must be at least:
  1. 56300W
  2. 62360W
  3. 48000W
  4. 66000W

Solution

Net force on motor will be
Fm=920+6810g+6000
=22000 N
So, required power for motor
Pm=F→m.v→
=22000×3
=66000 watt

Asked in: JEE Main 2020 (07 Jan Shift 2)

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