An element has electronic configuration $1 \mathrm{s}^{2} ~2 \mathrm{s}^{2} ~2 \mathrm{p}^{6} ~3…
An element has electronic configuration $1 \mathrm{s}^{2} ~2 \mathrm{s}^{2} ~2 \mathrm{p}^{6} ~3 \mathrm{s}^{2} ~3 \mathrm{p}^{6} ~3 \mathrm{d}^{10} ~4 \mathrm{s}^{2} ~4 \mathrm{p}^{6} 4 \mathrm{d}^{10} ~5 \mathrm{s}^{2} ~5 \mathrm{p}^{6} ~5 \mathrm{d}^{1} ~4 \mathrm{f}^{7} ~6 \mathrm{s}^{2}$. In which group should it be placed ?
Fifth
Thirteenth
Third
Seventeenth
Solution
It should be placed in the third group as the element loses $5 \mathrm{d}^{1}$ and $6 \mathrm{s}^{2}$ electrons to attain $+3$ oxidation state easily.