An element has electronic configuration $1 \mathrm{s}^{2} ~2 \mathrm{s}^{2} ~2 \mathrm{p}^{6} ~3…

An element has electronic configuration $1 \mathrm{s}^{2} ~2 \mathrm{s}^{2} ~2 \mathrm{p}^{6} ~3 \mathrm{s}^{2} ~3 \mathrm{p}^{6} ~3 \mathrm{d}^{10} ~4 \mathrm{s}^{2} ~4 \mathrm{p}^{6} 4 \mathrm{d}^{10} ~5 \mathrm{s}^{2} ~5 \mathrm{p}^{6} ~5 \mathrm{d}^{1} ~4 \mathrm{f}^{7} ~6 \mathrm{s}^{2}$. In which group should it be placed ?
  1. Fifth
  2. Thirteenth
  3. Third
  4. Seventeenth

Solution

It should be placed in the third group as the element loses $5 \mathrm{d}^{1}$ and $6 \mathrm{s}^{2}$ electrons to attain $+3$ oxidation state easily.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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