An element has $d^5$ configuration. The total number of electron exchanges possible for it is

An element has $d^5$ configuration. The total number of electron exchanges possible for it is
  1. $18$
  2. $10$
  3. $12$
  4. $15$

Solution

The total number of electron exchanges possibility is $\frac{n(n-1)}{2}$ (where, $n$ is the number of shells). By applying this formula for $d^5$ configuration we get, $=\frac{5(5-1)}{2}=\frac{5 \times 4}{2}=\frac{20}{2}=10$

Asked in: AP EAMCET 2022 (08 Jul Shift 2)

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