An element has BCC structure with edge length of unit cell 600 $\mathrm{pm}$. What is the atomic radius of…

An element has BCC structure with edge length of unit cell 600 $\mathrm{pm}$. What is the atomic radius of element?
  1. $\sqrt{3} \times 150 \mathrm{pm}$
  2. $150 \mathrm{pm}$
  3. $300 \mathrm{pm}$
  4. $\frac{300}{\sqrt{2}} \mathrm{pm}$

Solution

For BCC structure. $\begin{aligned} & \sqrt{3} \mathrm{a}=4 \mathrm{r} \\ & \mathrm{r}=\frac{\sqrt{3} \mathrm{a}}{4}=\frac{\sqrt{3} \times 600}{4} \\ & \mathrm{r}=\sqrt{3} \times 150 \mathrm{pm} \end{aligned}$

Asked in: MHT CET 2021 (24 Sep Shift 2)

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