An electron of mass m e and a proton of mass m P are accelerated through the same potential difference. The…

An electron of mass me and a proton of mass mP are accelerated through the same potential difference. The ratio of the de-Broglie wavelength associated with the electron to that with the proton is 
  1. mPme
  2. 1
  3. mpme
  4. memp

Solution

KE=eΔV
λe=h2 me(eΔV)
λp=h2 mp(eΔV)

⇒  λeλp=mpme

Asked in: JEE Main 2021 (22 Jul Shift 1)

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