An electron moves at right angle to a magnetic field of $5 imes 10^{-2} \mathrm{~T}$ with a speed of $6 imes 10^{7} \mathrm{~m} / \mathrm{s}$. If the specific charge of the electron is $1.7 imes 10^{11} \mathrm{C} / \mathrm{kg}$. The radius of the circular path will be

Question

An electron moves at right angle to a magnetic field of $5 	imes 10^{-2} \mathrm{~T}$ with a speed of $6 	imes 10^{7} \mathrm{~m} / \mathrm{s}$. If the specific charge of the electron is $1.7 	imes 10^{11} \mathrm{C} / \mathrm{kg}$. The radius of the circular path will be

Aicharya · Accepted Answer

Radius of circular path $\begin{aligned} \mathrm{r} &=\frac{\mathrm{mV}}{\mathrm{B}}=\frac{\mathrm{V}}{\left(\frac{\mathrm{e}}{\mathrm{m}}ight) \mathrm{B}} \ \mathrm{r} &=\frac{6 	imes 10^{7}}{1.7 	imes 10^{11} 	imes 15 	imes 10^{-2}} \ &=2.35 	imes 10^{-2} \mathrm{~m}=2.35 \mathrm{~m} \end{aligned}$

An electron moves at right angle to a magnetic field of $5 \times 10^{-2} \mathrm{~T}$ with a speed of $6…

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