An electron is moving around the nucleus of a hydrogen atom in a circular orbit of radius $r$. The coulomb…

An electron is moving around the nucleus of a hydrogen atom in a circular orbit of radius $r$. The coulomb force $\vec{F}$ between the two is: $\left(\right.$ where $\left.K=\frac{1}{4 \pi \varepsilon_0}\right)$
  1. $K \frac{e^2}{r^2} \hat{r}$
  2. $-K \frac{e^2}{r^3} \hat{r}$
  3. $K \frac{e^2}{r^3} \hat{r}$
  4. $-K \frac{e^2}{r^3} \hat{r}$

Solution

The charge on hydrogen nuclear $q_1$ $\begin{aligned} & =+v e \\ & \therefore \text { Coulomb's force } F=K \frac{q_1 q_2}{r^2} \\ & =K \frac{(+e)(-e)}{r^2}=-\frac{k e^2}{r^2} \hat{r} \end{aligned}$

Asked in: NEET 2003

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