An electron is accelerated through a potential difference of 10,000 V . Its de Broglie wavelength is…

An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is (nearly): me=9×10-31 kg
  1. 12.2×10-13 m
  2. 12.2×10-12 m
  3. 12.2×10-14 m
  4. 12.2 nm

Solution

The energy of electron K=104 eV
λ=hmv=h2mK=6.63×10-342×9.1×10-31×104×1.6×10-19≅12.2×10-12 m

Asked in: NEET 2019 (All India)

Practice more Dual Nature of Matter questions on Aicharya