An electron and a proton having same momenta enter perpendicular into a magnetic field then
An electron and a proton having same momenta enter perpendicular into a magnetic field then
they will move undeflected
curved path of electron and proton will be same. (Neglect sense of revolution)
curved path of electron is more curved than proton
path of the proton is more curved
Solution
The radius of curvature of a charged particle of mass $m$ and charge $q$ moving in a region with uniform perpendicular field $B$ is given by,
$r=\frac{m v}{B q}=\frac{p}{B q}$
where, $p$ is the momentum of the charged particle.
Since momenta are same and masses for electron and proton are different, so they will attain different velocities and hence experience different forces. But the radius of circular path is depending on momenta so both will be moving on same trajectory (curved path, neglecting the sense of revolution).
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