An electromagnetic wave of wavelength ' $\lambda$ ' is incident on a photosensitive surface of negligible…

An electromagnetic wave of wavelength ' $\lambda$ ' is incident on a photosensitive surface of negligible work function. If the photoelectrons emitted from this surface have the de-Broglie wavelength ' $\lambda_{1}{ }^{\prime}$ then
  1. $\lambda \propto \frac{1}{\lambda_{1}}$
  2. $\lambda \propto \lambda_{1}$
  3. $\lambda \propto \lambda_{1}^{2}$
  4. $\lambda \propto \frac{1}{\lambda_{1}^{2}}$

Solution

The de-Broglie wavelength of the emitted photoelectrons is related to the wavelength of the incident light. The correct relationship is given by:

Asked in: MHT CET 2020 (12 Oct Shift 2)

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