An electromagnetic wave of frequency $45 \mathrm{MHz}$ travels in free space along $X$-axis. At some point…
- $2.5 \times 10^{-6} \hat{\mathbf{j}}$
- $5 \times 10^{-6} \hat{\mathbf{k}} \mathrm{T}$
- $2.5 \times 10^{-6} \hat{\mathbf{k}} \mathrm{T}$
- $2.5 \times 10^{-6} \hat{\mathbf{i}} \mathrm{T}$
Solution
$\begin{aligned}
& B=\frac{E}{c} \\
& E=750 \mathrm{~N} / \mathrm{C}
\end{aligned}$
Speed of light,
$\begin{aligned}
c & =3 \times 10^8 \mathrm{~m} / \mathrm{s} \\
B & =\frac{750}{3 \times 10^8} \\
B & =2.5 \times 10^{-6} \mathrm{~T}
\end{aligned}$
As, $B$ must be perpendicular to both $\mathbf{c}$ and $\mathbf{E}$, i.e.it is along $Z$-axis.
$B=2.5 \times 10^{-6} \hat{\mathbf{k}} \mathrm{T}$
Asked in: AP EAMCET 2018 (24 Apr Shift 1)