
An electrical circuit consists of the resistances $R, r_1, R_2$ and voltage sources $E_1$ and $E_2$ as shown…

- $E_1-\left(I_1+I_2\right) R+I_2 r_2=0$
- $E_1-\left(I_1+I_2\right) R-I_1 r_1=0$
- $E_1-\left(I_1+I_2\right) R+I_1 r_1=0$
- $E_2-I_2 r_2-E_1-I_1 r_1=0$
Solution
Potential drop on moving along $E B C D E$ :
$\begin{aligned} & -I_1 r_1+E_2-\left(I_1+I_2\right) R=0 \\ & \Rightarrow E_2-\left(I_1+I_2\right) R-I_1 r_1=0\end{aligned}$Asked in: MHT CET 2022 (07 Aug Shift 2)