An electric dipole of moment p → = - i ^ - 3 j ^ + 2 k ^ × 10 - 29   C m at the origin…

An electric dipole of moment p=-i^-3j^+2k^×10-29 C m at the origin 0,0,0 . The electric field due to this dipole at r=+i^+3j^+5k^ (note that rp=0 ) is parallel to:
  1. +i^-3j^-2k^
  2. -i^+3j^-2k^
  3. +i^+3j^-2k^
  4. -i^-3j^+2k^

Solution

As r·p=0, this means that r is perpendicular to p.

For an electric dipole, electric field at equatorial position is antiparallel to p.

E=-λp,

where, λ is an arbitrary positive constant.

E=-λ-i^-3j^+2k^×10-29 C m-2

E=λi^+3j^-2k^×10-29 C m-2

For λ=110-29 

E=i^+3j^-2k^ C m-2

Asked in: JEE Main 2020 (09 Jan Shift 1)

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