An electric dipole of dipole moment $6 \times 10^{-6} \mathrm{Cm}$ is placed in uniform electric field of…

An electric dipole of dipole moment $6 \times 10^{-6} \mathrm{Cm}$ is placed in uniform electric field of magnitude $10^6 \mathrm{~V} / \mathrm{m}$. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be ____ J.

Solution

Work done in rotating a dipole $=\Delta U$
$\text { or } \begin{aligned}
W & =\left(-P E \cos \theta_f\right)-\left(-P E \cos \theta_i\right) \\ & =2 P E \quad\left(\because \theta_f=180^{\circ} \text { and } \theta_i=0^{\circ}\right) \\ & =\left(2 \times 6 \times 10^{-6} \times 10^6\right) \mathrm{J}=12 \mathrm{~J}
\end{aligned}$

Asked in: JEE Main 2025 (28 Jan Shift 2)

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