An electric bulb of 500   W at 100   V is used in a circuit having a 200   V supply.…

An electric bulb of 500 W at 100 V is used in a circuit having a 200 V supply. Calculate the resistance R to be connected in series with the bulb so that the power delivered by the bulb is 500 W.
  1. 30 Ω
  2. 5 Ω
  3. 20 Ω
  4. 10 Ω

Solution

Resistance of bulb

P=V2r

r=(100)2500=100×100500=20

i=PV=500100=5 A

ΔV in resistance R=100 V

R=1005=20 Ω

Asked in: JEE Main 2021 (26 Aug Shift 2)

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