An average induced emf of $0.5 \mathrm{~V}$ appears in a coil when the current in it is changed from $10 \mathrm{~A}$ in one direction to $10 \mathrm{~A}$ in opposite direction in 0.8 second. The self-inductance of the coil is

Question

Aicharya · Accepted Answer

$\begin{aligned} & e=L \frac{d i}{d t}=L \times \frac{20}{0.8}=25 L=0.5 \mathrm{~V} \ & \Rightarrow L=\frac{1}{50} H=0.02 \mathrm{H}=20 \mathrm{H}\end{aligned}$

An average induced emf of $0.5 \mathrm{~V}$ appears in a coil when the current in it is changed from $10…

Solution