An atom in a molecule has electrons in $1 s, 2 s, 2 p, 3 s, 3 p, 3 d$ and $4 s$ orbitals. This atoms can…
An atom in a molecule has electrons in $1 s, 2 s, 2 p, 3 s, 3 p, 3 d$ and $4 s$ orbitals. This atoms can undergo hybridisations of type
$s p^3 d^2, s p^3, p^3 d s$
$d^2 s p^3, p^2 d s, d s p^2$
$s p^3, d s p^2, d^2 s p^3$
$s p^3, d s p^2, d s p$
Solution
An atom in a molecule has electrons in $1 s, 2 s$, $2 p, 3 s, 3 p, 3 d$ and $4 s$-orbitals. Thus, the outermost most valence shell composed of $3 d$-orbitals. $3 d$-orbitals can form inner and outer orbital complex depending upon the types of ligands present. It can undergoes hybridisation of type $s p^3$ (e.g. $\left.\left[\mathrm{NiCl}_4\right]^{2-}\right), d s p^2\left(\mathrm{e} . \mathrm{g}\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}\right), s p^3 d^2$ (e.g. $\left[\mathrm{CoF}_6\right]^{3-} d^2 s p^3$ (e.g. $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ ), $d s p^3\left(\mathrm{e} . \mathrm{g} \cdot\left[\mathrm{Fe}(\mathrm{CO})_5\right]\right.$