An asteroid is moving directly towards the centre of the earth. When at a distance of 10 R ( R is the radius…

An asteroid is moving directly towards the centre of the earth. When at a distance of 10R (R is the radius of the earth) from the centre of the earth, it has a speed of 12 km s-1. Neglecting the effect of earth's atmosphere, what will be the speed of the asteroid when it hits the surface of the earth (escape velocity from the earth is 11.2 km s-1) ? Give your answer to the nearest integer in km s-1__________.

Solution

KEi+PEi=KEf+PEf
12mu02+-GMm10R=12mv2+-GMmR
v2=u02+2GMR1-110
v=u02+95GMR

=122+9511.222
=144+0.911.22=156.896

=16.028 km s-1

16 km s-1 

Asked in: JEE Main 2020 (08 Jan Shift 2)

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