An artillery piece of mass M 1 fires a shell of mass M 2 horizontally. Instantaneously after the firing, the…

An artillery piece of mass M1 fires a shell of mass M2 horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is :
  1. M1(M1+M2)
  2. M2M1
  3. M2(M1+M2)
  4. M1M2

Solution

As linear momentum will be conserved, p⇀1=p⇀2

Now, kinetic energy can be written as KE=p22M.

Also p is the same for both masses. We can write,

KE∝1m

⇒KE1KE2=p22M1p22M2=M2M1

Asked in: JEE Main 2024 (31 Jan Shift 1)

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