An artificial cell is made by encapsulating \(0.2 \mathrm{M}\) glucose solution within a semipermeable…
Solution

$\begin{aligned} & \mathrm{NaCl} \longrightarrow \mathrm{Na}^{+}+\mathrm{Cl}^{-} \\ & 0.05 \mathrm{M} \quad 0.05 \mathrm{M} \quad 0.05 \mathrm{M} \\ & \text { Total } \mathrm{C}_1=0.05+0.05=0.1 \mathrm{M}(\mathrm{NaCl}) \\ & \mathrm{C}_2=0.2 \mathrm{M}(\text { glucose }) \\ & \pi=\left(\mathrm{C}_2-\mathrm{C}_1\right) \mathrm{RT} \\ & =(0.2-0.1) \times 0.083 \times 300 \\ & =2.49 \mathrm{bar} \\ & =24.9 \times 10^{-1} \text { bar }\end{aligned}$
Asked in: JEE Main 2024 (05 Apr Shift 1)