An aromatic ether is not cleaved by HI even at $525 \mathrm{~K}$. The compound is
- $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OCH}_{3}$
- $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OC}_{6} \mathrm{H}_{5}$
- $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OC}_{3} \mathrm{H}_{7}$
- Tetrahydrofuran
Solution
Asked in: JEE-TOPICTESTS-CHEMISTRY
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