An anion solution gives a white ppt with $\mathrm{AgNO}_{3}$ solution. The ppt. dissolves in dil. ammonia…
ammonia due to the formation of
- $\mathrm{AgNO}_{3}$
- $\mathrm{NH}_{4} \mathrm{NO}_{3}$
- $\left\lfloor\mathrm{Ag}\left(\mathrm{NH}_{3}ight)_{2}ight] \mathrm{Cl}$
- $\left\lfloor\mathrm{Ag}\left(\mathrm{NH}_{3}ight)_{2}ightfloor \mathrm{Br}$
Solution
$\mathrm{AgCl}+2 \mathrm{NH}_{3} ightarrow\left[\mathrm{Ag}\left(\mathrm{NH}_{3}ight)_{2}ight] \mathrm{Cl}$
Asked in: JEE-TOPICTESTS-CHEMISTRY