An AND gate is followed by a NOT gate in series. With two inputs 'A' and 'B', the Boolean expression for the…
- $\overline{\mathrm{A}+\mathrm{B}}$
- $\overline{\mathrm{A} \cdot \mathrm{B}}$
- $\mathrm{A} \cdot \mathrm{B}$
- $\mathrm{A}+\mathrm{B}$
Solution
The combination of an AND gate followed by a NOT gate forms a NAND gate. The AND gate output is the logical product $A \cdot B$, which serves as input to the NOT gate. Inversion yields the final output $Y = \overline{A \cdot B}$.
This expression corresponds to option B among the choices, identifying the configuration as a NAND gate rather than NOR, AND, or OR operations.
Final answer: $\boxed{B}$
Asked in: MHT CET 2025 (05 May Shift 2)