An aluminium (resistivity $\rho=2.2 \times 10^{-8} \Omega$-m) wire of a diameter $1.4 \mathrm{~mm}$ is used…
An aluminium (resistivity $\rho=2.2 \times 10^{-8} \Omega$-m) wire of a diameter $1.4 \mathrm{~mm}$ is used to make a $4 \Omega$ resistor. The length of the wire is
$220 \mathrm{~m}$
$1000 \mathrm{~m}$
$280 \mathrm{~m}$
$1 \mathrm{~m}$
Solution
Length of the wire is
$\begin{array}{rl}\quad l & =\frac{R A}{\rho} \\ \therefore \quad l & l \\ \therefore \quad & \frac{4 \times \pi \times\left(0.7 \times 10^{-3}\right)^2}{2.2 \times 10^{-8}} \\ & =280 \mathrm{~m}\end{array}$