An alternating voltage source V = 260 sin ( 628 t ) is connected across a pure inductor of 5   mH . Inductive reactance in the circuit is:

Question

An alternating voltage source V = 260 sin ( 628 t ) is connected across a pure inductor of 5 &#160; mH . Inductive reactance in the circuit is:

Aicharya · Accepted Answer

Comparing the given equation of AC voltage with standard expression, $V = V_{0} \sin (ω t)$ , we get $ω = 628 rad s^{- 1}$ .

Inductive reactance is given by, $X_{L} = ω L$ .

$= 628 \times (5 \times 10^{- 3})$

$= 3.14 Ω$

An alternating voltage source V = 260 sin ( 628 t ) is connected across a pure inductor of 5   mH .…