An alternating voltage is represented by $\mathrm{V}=80 \sin (100 \pi \mathrm{t})$ $\cos (100 \pi…
An alternating voltage is represented by $\mathrm{V}=80 \sin (100 \pi \mathrm{t})$ $\cos (100 \pi \mathrm{t})$ volt. The peak voltage is
$20 \mathrm{~V}$
$40 \mathrm{~V}$
$30 \mathrm{~V}$
$50 \mathrm{~V}$
Solution
$\mathrm{V}=80 \sin (100 \pi \mathrm{t}) \cos (100 \pi \mathrm{t})=40 \sin 200 \pi \mathrm{t}$
Amplitude or the peak value of the voltage $=40 \mathrm{~V}$