An alternating e.m.f. is $\mathrm{e}=\mathrm{e}_0 \sin \omega \mathrm{t}$. In what time the e.m.f. will have half its maximum value, if ' $\mathrm{e}$ ' starts from zero? ( $\mathrm{T}=$ time period)

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Aicharya · Accepted Answer

$\mathrm{e}=\mathrm{e}_0 \sin \omega \mathrm{t}$ If $\mathrm{e}=\frac{\mathrm{e}_0}{2}$ then $\frac{\mathrm{e}_0}{2}=\mathrm{e}_0 \sin \omega \mathrm{t}$ $\begin{aligned} & \sin \omega \mathrm{t}=\frac{1}{2} \ & \omega \mathrm{t}=30^{\circ}=\frac{\pi}{6} \mathrm{rad} \ & \frac{2 \pi}{\mathrm{T}} \cdot \mathrm{t}=\frac{\pi}{6} \ & \mathrm{t}=\frac{\mathrm{T}}{12}\end{aligned}$ ~

An alternating e.m.f. is $\mathrm{e}=\mathrm{e}_0 \sin \omega \mathrm{t}$. In what time the e.m.f. will have…

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