An alternating current is given by $\mathrm{I}=\mathrm{I}_{1} \sin \omega \mathrm{t}+\mathrm{I}_{2} \cos \omega \mathrm{t}$. The r.m.s current will be

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Aicharya · Accepted Answer

$\begin{aligned} & \frac{1}{\sqrt{2}}\left(\mathrm{i}_1^2+\mathrm{i}_2^2\right)^{\frac{1}{2}} \ & \mathrm{i}=\mathrm{i}_1 \sin \omega \mathrm{t}+\mathrm{i}_2 \sin (\omega \mathrm{t}+90) \ & \mathrm{i}=\sqrt{\mathrm{i}_1^2+\mathrm{i}_2^2} \sin (\omega \mathrm{t}+\phi) \ & \mathrm{i}_{\mathrm{ms}}=\frac{\mathrm{i}_0}{\sqrt{2}} \ & =\frac{\sqrt{\mathrm{i}_1^2+\mathrm{i}_2^2}}{\sqrt{2}} \end{aligned}$

An alternating current is given by $\mathrm{I}=\mathrm{I}_{1} \sin \omega \mathrm{t}+\mathrm{I}_{2} \cos…

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