An alpha nucleus of energy $\frac{1}{2} m v^2$ bombards a heavy nuclear target of charge Ze. Then the…

An alpha nucleus of energy $\frac{1}{2} m v^2$ bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
  1. $\frac{1}{\mathrm{Ze}}$
  2. $v^2$
  3. $\frac{1}{m}$
  4. $\frac{1}{v^4}$

Solution

$\frac{1}{m}$

Asked in: JEE Main 2006

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