An alcohol on oxidation is found to give $\mathrm{CH}_{3} \mathrm{COOH}$ and $\mathrm{CH}_{3}…
- $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}$
- $\left(\mathrm{CH}_{3}ight)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CH}_{2} \mathrm{CH}_{3}$
- $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHOHCH}_{3}$
- $\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}$
Solution
.Asked in: JEE-TOPICTESTS-CHEMISTRY
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