An acid dissociated to $1.5 \%$ in its $0.1 \mathrm{M}$ solution. Calculate its dissociation constant.
An acid dissociated to $1.5 \%$ in its $0.1 \mathrm{M}$ solution. Calculate its dissociation constant.
- $1.2 \times 10^{-5}$
- $2.25 \times 10^{-5}$
- $1.1 \times 10^{-5}$
- $1.5 \times 10^{-5}$
Solution
$\begin{aligned} & K_a=\alpha^2 C \\ & =\left(\frac{1.5}{100}\right)^2 \times 0.1 \\ & =2.25 \times 10^{-5}\end{aligned}$
Asked in: MHT CET 2022 (06 Aug Shift 2)
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