An acid-base indicator has a $\mathrm{K}_{\mathrm{a}}$ of $3.0 \times 10^{-5} .$ The acid form of the…
- $\mathrm{pH}$ is $4.05$ when indicator is $75 \%$ red
- $\mathrm{pH}$ is $5.00$ when indicator is $75 \%$ red
- $\mathrm{pH}$ is $4.05$ when indicator is $75 \%$ blue
- none of these
Solution
Red blue
$\mathrm{pH}=\mathrm{pK}_{\mathrm{ln}}+\log \frac{\left[\mathrm{ln}^{-}ight]}{[\mathrm{Hln}]}$
$(5-\log 3)+\log \left(\frac{25}{75}ight)$
$\mathrm{pH}$ is $4.05$ when the indicator is $75 \%$ red.
Asked in: JEE-TOPICTESTS-CHEMISTRY