Amongst the given options, the compound (s) in which all the atoms are in one plane in all the possible…

Amongst the given options, the compound (s) in which all the atoms are in one plane in all the possible conformations (if any), is (are)




Solution

$ \text { In both (b) and (c), all the atoms are present in one single plane } $
In (a) 1, 3-butadiene, conformational change is possible between $\mathrm{C}_2-\mathrm{C}_3$ bond in which atoms will be present in more than one single plane. In (d) allene, the terminals $\mathrm{H}-\mathrm{C}-\mathrm{H}$ planes are perpendicular to one another. $ \text { Paragraph (12 and 13) The final ozonolysis product indicates that the alkene before } $ Ozonolysis is
Also $\mathrm{P}\left(\mathrm{C}_6 \mathrm{H}_{10}\right)$ has two degree of unsaturation and oxymercuration demercuration hydration indicates that it is an alkyne. As alkyne, on hydration, gives a carbonyl compound which on reduction with $\mathrm{NaBH}_4$ gives a $2^{\circ}$ alcohol.

Asked in: JEE Advanced 2011 (Paper 1)

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