Among the oxyacids of chlorine, the order of acidic character is
- $\mathrm{HClO}_4 < \mathrm{HClO}_3 < \mathrm{HClO}_2 < \mathrm{HOCl}$
- $\mathrm{HOCl} < \mathrm{HClO}_2 < \mathrm{HClO}_3 < \mathrm{HClO}_4$
- $\mathrm{HClO}_2 < \mathrm{HClO} < \mathrm{HClO}_3 < \mathrm{HClO}_4$
- $\mathrm{HClO}_3 < \mathrm{HClO}_2 < \mathrm{HOCl} < \mathrm{HClO}_4$
Solution
Asked in: AP EAMCET 2017 (24 Apr Shift 1)
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