Among $\mathrm{V}, \mathrm{Cr}, \mathrm{Zn}, \mathrm{Fe}$, the metal having lowest enthalpy of atomization is
Among $\mathrm{V}, \mathrm{Cr}, \mathrm{Zn}, \mathrm{Fe}$, the metal having lowest enthalpy of atomization is
- V
- $\mathrm{Cr}$
- $\mathrm{Zn}$
- $\mathrm{Fe}$
Solution
Due to absence of unpaired electrons, $\mathrm{Zn}$ has the lowest enthalpy of atomization.
Asked in: AP EAMCET 2023 (17 May Shift 1)
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