Among the following, the correctly matched pair is
Among the following, the correctly matched pair is
electron deficient hydride $-\mathrm{SiH}_4$
saline hydride - $\mathrm{CrH}$
electron precise hydride - HF
electron rich hydride $-\mathrm{NH}_3$
Solution
$\mathrm{NH}_3$ is an electron-rich hydride as $\mathrm{N}$-atom belongs to group - 15 and uses three of its valence electrons to make three $\mathrm{N}-\mathrm{H}$ bonds and the remaining two electrons form a lone pair.