Aluminum carbide on reaction with $\mathrm{D}_2 \mathrm{O}$ gives $\mathrm{Al}(\mathrm{OD})_3$ and ' X '.…

Aluminum carbide on reaction with $\mathrm{D}_2 \mathrm{O}$ gives $\mathrm{Al}(\mathrm{OD})_3$ and ' X '. What is ' X '?
  1. $\mathrm{C}_2 \mathrm{D}_2$
  2. $\mathrm{C}_3 \mathrm{D}_4$
  3. $\mathrm{C}_2 \mathrm{D}_4$
  4. $\mathrm{CD}_4$

Solution

$\begin{aligned} & \text { Aluminium Carbide }=\mathrm{Al}_4 \mathrm{C}_3 \\ & \mathrm{Al}_4 \mathrm{C}_3=\mathrm{Al}^{3+} \text { or } \mathrm{C}^{-}\end{aligned}$ Now, satisfy the value of $\mathrm{C}^4$ $\mathrm{Al}_4 \mathrm{C}_3+12 \mathrm{D}_2 \mathrm{O} \rightarrow 4 \mathrm{Al}(\mathrm{OD})_3+3 \mathrm{CD}_4$

Asked in: AP EAMCET 2024 (18 May Shift 1)

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