Aluminium crystallises in a face centred cubic structure, it's atomic radius is $125 \mathrm{pm} .$ What is…
Aluminium crystallises in a face centred cubic structure, it's atomic radius is $125 \mathrm{pm} .$ What is
the edge length of unit cell?
- $280 \mathrm{pm}$
- $353.5 \mathrm{pm}$
- $335.5 \mathrm{pm}$
- $288.6 \mathrm{pm}$
Solution
For fcc unit cell, $r=\frac{a}{2 \sqrt{2}}$
$\therefore a=r(2 \sqrt{2})=125(2 \sqrt{2})=353.5 \mathrm{pm}$
Asked in: MHT CET 2020 (14 Oct Shift 2)
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