Airplanes A and B are flying with constant velocity in the same vertical plane at angles $30^{o}$ and $60^{o}$ with respect to the horizontal respectively as shown in the figure. The speed of A is $100 \sqrt{3} m s^{- 1}$ . At time t = 0 s, an observer in A finds B at a distance of 500 m. This observer sees B moving with a constant velocity perpendicular to the line of motion of A. If at $t = t_{0}$ , A just escapes being hit by B, t₀ in seconds is

Question

Aicharya · Accepted Answer

The relative velocity of B with respect to A is perpendicular to line of motion of A.

∴ V_{B} \cos 30^{o} = V_{A}

\Rightarrow V_{B} = 200

m/s
And time

t_{0} = \frac{(R e l a t i v e d i s t a n c e)}{(R e l a t i v e v e l o c i t y)}

= \frac{500}{V_{B} \sin 30^{o}} = 5 s e c

Airplanes A and B are flying with constant velocity in the same vertical plane at angles 30 o and 60 o with…

Solution