After marking $X$, join $XC$ and draw the perpendicular bisector of $XC$. It meets ray $BX$ extended at

After marking $X$, join $XC$ and draw the perpendicular bisector of $XC$. It meets ray $BX$ extended at
  1. $A$
  2. $B$
  3. midpoint of $BC$
  4. infinity

Solution

$A$ lies on this perpendicular bisector and on the ray.

Asked in: MH-SSC-9

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