After balancing equation, $\mathrm{C}_2 \mathrm{O}_4^{2-}+\mathrm{H}^{+}+\mathrm{MnO}_4^{-} \longrightarrow \mathrm{CO}_2+\mathrm{Mn}^{2+}+\mathrm{H}_2 \mathrm{O}$ The coefficient of $\mathrm{CO}_2$ is

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Aicharya · Accepted Answer

$\begin{aligned} & a \stackrel{+3}{\mathrm{C}_2} \mathrm{O}_4^{2-}+b \stackrel{+7}{\mathrm{M}} \mathrm{O}_4^{-}+\mathrm{H}^{+} \rightarrow p \stackrel{+4}{\mathrm{CO}_2}+q \mathrm{Mn}^{2+}+\mathrm{H}_2 \mathrm{O} \ & \text {nf }(4-3) \times 2=2(7-2) \times 1=5 \ & \text {mole: } \quad 5 \ \end{aligned}$ $\Rightarrow \quad a=5, b=2$ $\Rightarrow$ By POAC, for C-atoms: $2 a=p$ $p=2 a=2 \times 5=10$ (Here, $n f: n$-factor or valency factor)

After balancing equation, \(\mathrm{C}_2 \mathrm{O}_4^{2-}+\mathrm{H}^{+}+\mathrm{MnO}_4^{-} \longrightarrow…

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