Addition of sodium thiosulphate solution to a solution of silver nitrate gives $X$ as white precipitate,…

Addition of sodium thiosulphate solution to a solution of silver nitrate gives $X$ as white precipitate, insoluble in water but soluble in excess thiosulphate solution to give $Y$. On boiling in water, $Y$ gives $Z . X, Y$ and $Z$ respectively are
  1. $\mathrm{Ag}_{2} \mathrm{S}_{2} \mathrm{O}_{3} \cdot \mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}ight)_{2}ight], \mathrm{Ag}_{2} \mathrm{S}$
  2. $\mathrm{Ag}_{2} \mathrm{SO}_{4}, \mathrm{Na}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}ight)_{2}ight], \mathrm{Ag}_{2} \mathrm{S}_{2}$
  3. $\mathrm{Ag}_{2} \mathrm{S}_{2} \mathrm{O}_{3} \cdot \mathrm{Na}_{5}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}ight)_{3}ight], \mathrm{AgS}$
  4. $\mathrm{Ag}_{2} \mathrm{SO}_{3} \cdot \mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}ight)_{2}ight], \mathrm{Ag}_{2} \mathrm{O}$

Solution

The sequence of reactions are


Hence, $X=A g_{2} S_{2} O_{3}$
$$
Y=\mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}ight)_{2}ight] Z=\mathrm{Ag}_{2} \mathrm{S}
$$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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