Addition of excess aqueous ammonia to a pink coloured aqueous solution of M C l 2 . 6 H 2 O   ( X ) and N H 4 C l gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1 : 3 electrolyte. The reaction of X with excess HCl at room temperature results in…

Question

Addition of excess aqueous ammonia to a pink coloured aqueous solution of

M C l_{2} . 6 H_{2} O (X)

and

N H_{4} C l

gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1 : 3 electrolyte. The reaction of X with excess HCl at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for complex Y.
Among the following options, which statement(s) is(are) correct ?

Aicharya · Accepted Answer

Cobalt salts are pink in anhydrous & blue in hydrated form

(i) Hybridisation of (Y) is $d^{2} s p^{3}$ as $N H_{3}$ is a strong field ligand

(ii) ${[C o C l_{4}]}^{2 -}$ have $s p^{3}$ hybridisation as $C l^{-}$ is a weak field ligand

(iii)

(iv)

!

Addition of excess aqueous ammonia to a pink coloured aqueous solution of M C l 2 . 6 H 2 O   ( X ) and…

Solution

Addition of excess aqueous ammonia to a pink coloured aqueous solution of M C l 2 . 6 H 2 O &#160; ( X ) and…

Solution

Addition of excess aqueous ammonia to a pink coloured aqueous solution of M C l 2 . 6 H 2 O ( X ) and…