Acidification of chromate gives ' $Z$ '. The oxidation state of chromium in ' $Z$ ' is

Acidification of chromate gives ' $Z$ '. The oxidation state of chromium in ' $Z$ ' is
  1. +3
  2. +6
  3. +7
  4. +2

Solution

$2 \mathrm{Na}_2 \mathrm{CrO}_4+2 \mathrm{H}^{+} \longrightarrow \mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7+2 \mathrm{Na}^{+}+\mathrm{H}_2 \mathrm{O}$ $\begin{aligned} & \mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7: \\ & (+2)+(2 \mathrm{x})-(14)=0 \\ & 2 \mathrm{x}-12=0 \\ & x=6\end{aligned}$

Asked in: AP EAMCET 2024 (23 May Shift 1)

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