Acetaldoxime reacts with $\mathrm{P}_{2} \mathrm{O}_{5}$ to give
Acetaldoxime reacts with $\mathrm{P}_{2} \mathrm{O}_{5}$ to give
- Methyl cyanide
- Methyl cyanate
- Ethyl cyanide
- None of these
Solution
$\mathrm{CH}_{3} \mathrm{CH}=\mathrm{NOH} \stackrel{\mathrm{P}_{2} \mathrm{O}_{5}}{\longrightarrow} \mathrm{CH}_{3} \mathrm{CN}+\mathrm{H}_{2} \mathrm{O}$
Asked in: JEE-TOPICTESTS-CHEMISTRY
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