Acetaldehyde reacts with semicarbazide and forms semicarbazone. Its structure is

Acetaldehyde reacts with semicarbazide and forms semicarbazone. Its structure is
  1. $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{NNHCON}=\mathrm{CHCH}_{3}$
  2. $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{NNHCONH}_{2}$
  4. $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{N}-\mathrm{CONHNH}_{2}$

Solution

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Asked in: JEE-TOPICTESTS-CHEMISTRY

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